Learn More PERT CPM Chart and Critical Path Calculate the critical path of the project and its PERT-CPM diagram. Simplex method calculator - Solve the Linear programming problem using Simplex method, step-by-step online. {\displaystyle z} Have we optimized the function? 4 {\displaystyle z_{i}} {\displaystyle {\begin{array}{c c c c c c c | r}x_{1}&x_{2}&x_{3}&s_{1}&s_{2}&s_{3}&z&b\\\hline 1&0.5&0.5&0.5&0&0&0&1\\0&0.6&1&-0.2&0.4&0&0&1.2\\0&1&0&-1&0&1&0&6\\\hline 0&1&-2&2&0&0&1&4\end{array}}}, By performing the row operation to make other columns 0's, the following could be derived, x considered as a Minimization calculator. 4 x \left[\begin{array}{ccccc|c} i 2 Author: Guoqing Hu (SysEn 6800 Fall 2020), Simplex algorithm (or Simplex method) is a widely-used algorithm to solve the Linear Programming(LP) optimization problems. calculator TI 84 plus. 1 Step 2: To get the optimal solution of the linear problem, click WebSimplex method calculator - Solve the Linear programming problem using Simplex method, step-by-step online. 0 PHPSimplex is able to solve problems using the Simplex method, Two-Phase method, and Graphical method, and has no limitations on the number of decision variables nor on constraints in the problems. Math Questions. WebLinear programming simplex calculator Do my homework for me. x j 1 . 0 Nivrutti Patil. WebStep 1: In the given respective input field, enter constraints, and the objective function. Springer, New York, NY. Springer Texts in Electrical Engineering. 2 Hence, the following equation can be derived: x j WebLinear Programming Solver Linear Programming Added Jul 31, 2018 by vik_31415 in Mathematics Linear programming solver with up to 9 variables. j The smaller value is in row one, so we choose that row. 0 & 7 & -4.23 & 2.81 & 0 & 8.38 \\ =, x 2? 2 0 Then make equations out of the inequalities. Conic Sections: Parabola and Focus. For this solution, the first column is selected. 1 i . \[ Thumbnail: Polyhedron of simplex algorithm in 3D. It can also help improve your math skills. , value which should be optimized, and the constraints are used to 9.3: Minimization By The Simplex Method. 0 , Step 1: In the given respective input field, enter constraints, . Calculator TI 84 plus. Finally, the simplex method requires that the objective function be listed as the bottom line in the matrix so that we have: The name of the algorithm is derived from the concept of a simplex and was suggested by T. S. Motzkin. WebeMathHelp Math Solver - Free Step-by-Step Calculator Solve math problems step by step This advanced calculator handles algebra, geometry, calculus, probability/statistics, Minimize 5 x 1? It is based on the theorem that if a system In this,
to the end of the list of x-variables with the following expression: calculator is that you do not need to have any language to state
Finding a maximum value of the function Example 2. Juan Jos Ruiz Ruiz, English translation by:
On the right-hand side of each constant do not enter any e
+ 3 x 2? In order to be able to find a solution, we need problems in the form of a standard maximization problem. i The online simplex method calculator or simplex solver, plays an
Traveling Salesman Problem. Accessibility StatementFor more information contact us atinfo@libretexts.orgor check out our status page at https://status.libretexts.org. For the Simplex algorithm, the coefficient with the least value is preferred since the major objective is maximization. 1 All rights reserved. WebLinear Programming Project Graph. In 1979, a Soviet scientist named Leonid Khachian developed a method called the ellipsoid algorithm which was supposed to be {\displaystyle \max \sum _{i=1}^{n}c_{i}x_{i}}, s \nonumber\]. , Solve linear programming maximization problems using the simplex method. 3 . The first operation can be used at most 600 hours; the second at most 500 hours; and the third at most 300 hours. P1 = (P1 * x3,6) - (x1,6 * P3) / x3,6 = ((245 * 0.4) - (-0.3 * 140)) / 0.4 = 350; P2 = (P2 * x3,6) - (x2,6 * P3) / x3,6 = ((225 * 0.4) - (0 * 140)) / 0.4 = 225; P4 = (P4 * x3,6) - (x4,6 * P3) / x3,6 = ((75 * 0.4) - (-0.5 * 140)) / 0.4 = 250; P5 = (P5 * x3,6) - (x5,6 * P3) / x3,6 = ((0 * 0.4) - (0 * 140)) / 0.4 = 0; x1,1 = ((x1,1 * x3,6) - (x1,6 * x3,1)) / x3,6 = ((0 * 0.4) - (-0.3 * 1)) / 0.4 = 0.75; x1,2 = ((x1,2 * x3,6) - (x1,6 * x3,2)) / x3,6 = ((0 * 0.4) - (-0.3 * 0)) / 0.4 = 0; x1,3 = ((x1,3 * x3,6) - (x1,6 * x3,3)) / x3,6 = ((1 * 0.4) - (-0.3 * 0)) / 0.4 = 1; x1,4 = ((x1,4 * x3,6) - (x1,6 * x3,4)) / x3,6 = ((0 * 0.4) - (-0.3 * 0)) / 0.4 = 0; x1,5 = ((x1,5 * x3,6) - (x1,6 * x3,5)) / x3,6 = ((-0.4 * 0.4) - (-0.3 * 0.2)) / 0.4 = -0.25; x1,6 = ((x1,6 * x3,6) - (x1,6 * x3,6)) / x3,6 = ((-0.3 * 0.4) - (-0.3 * 0.4)) / 0.4 = 0; x1,8 = ((x1,8 * x3,6) - (x1,6 * x3,8)) / x3,6 = ((0.3 * 0.4) - (-0.3 * -0.4)) / 0.4 = 0; x1,9 = ((x1,9 * x3,6) - (x1,6 * x3,9)) / x3,6 = ((0 * 0.4) - (-0.3 * 0)) / 0.4 = 0; x2,1 = ((x2,1 * x3,6) - (x2,6 * x3,1)) / x3,6 = ((0 * 0.4) - (0 * 1)) / 0.4 = 0; x2,2 = ((x2,2 * x3,6) - (x2,6 * x3,2)) / x3,6 = ((0 * 0.4) - (0 * 0)) / 0.4 = 0; x2,3 = ((x2,3 * x3,6) - (x2,6 * x3,3)) / x3,6 = ((0 * 0.4) - (0 * 0)) / 0.4 = 0; x2,4 = ((x2,4 * x3,6) - (x2,6 * x3,4)) / x3,6 = ((1 * 0.4) - (0 * 0)) / 0.4 = 1; x2,5 = ((x2,5 * x3,6) - (x2,6 * x3,5)) / x3,6 = ((0 * 0.4) - (0 * 0.2)) / 0.4 = 0; x2,6 = ((x2,6 * x3,6) - (x2,6 * x3,6)) / x3,6 = ((0 * 0.4) - (0 * 0.4)) / 0.4 = 0; x2,8 = ((x2,8 * x3,6) - (x2,6 * x3,8)) / x3,6 = ((0 * 0.4) - (0 * -0.4)) / 0.4 = 0; x2,9 = ((x2,9 * x3,6) - (x2,6 * x3,9)) / x3,6 = ((0 * 0.4) - (0 * 0)) / 0.4 = 0; x4,1 = ((x4,1 * x3,6) - (x4,6 * x3,1)) / x3,6 = ((0 * 0.4) - (-0.5 * 1)) / 0.4 = 1.25; x4,2 = ((x4,2 * x3,6) - (x4,6 * x3,2)) / x3,6 = ((1 * 0.4) - (-0.5 * 0)) / 0.4 = 1; x4,3 = ((x4,3 * x3,6) - (x4,6 * x3,3)) / x3,6 = ((0 * 0.4) - (-0.5 * 0)) / 0.4 = 0; x4,4 = ((x4,4 * x3,6) - (x4,6 * x3,4)) / x3,6 = ((0 * 0.4) - (-0.5 * 0)) / 0.4 = 0; x4,5 = ((x4,5 * x3,6) - (x4,6 * x3,5)) / x3,6 = ((0 * 0.4) - (-0.5 * 0.2)) / 0.4 = 0.25; x4,6 = ((x4,6 * x3,6) - (x4,6 * x3,6)) / x3,6 = ((-0.5 * 0.4) - (-0.5 * 0.4)) / 0.4 = 0; x4,8 = ((x4,8 * x3,6) - (x4,6 * x3,8)) / x3,6 = ((0.5 * 0.4) - (-0.5 * -0.4)) / 0.4 = 0; x4,9 = ((x4,9 * x3,6) - (x4,6 * x3,9)) / x3,6 = ((0 * 0.4) - (-0.5 * 0)) / 0.4 = 0; x5,1 = ((x5,1 * x3,6) - (x5,6 * x3,1)) / x3,6 = ((0 * 0.4) - (0 * 1)) / 0.4 = 0; x5,2 = ((x5,2 * x3,6) - (x5,6 * x3,2)) / x3,6 = ((0 * 0.4) - (0 * 0)) / 0.4 = 0; x5,3 = ((x5,3 * x3,6) - (x5,6 * x3,3)) / x3,6 = ((0 * 0.4) - (0 * 0)) / 0.4 = 0; x5,4 = ((x5,4 * x3,6) - (x5,6 * x3,4)) / x3,6 = ((0 * 0.4) - (0 * 0)) / 0.4 = 0; x5,5 = ((x5,5 * x3,6) - (x5,6 * x3,5)) / x3,6 = ((0 * 0.4) - (0 * 0.2)) / 0.4 = 0; x5,6 = ((x5,6 * x3,6) - (x5,6 * x3,6)) / x3,6 = ((0 * 0.4) - (0 * 0.4)) / 0.4 = 0; x5,8 = ((x5,8 * x3,6) - (x5,6 * x3,8)) / x3,6 = ((0 * 0.4) - (0 * -0.4)) / 0.4 = 0; x5,9 = ((x5,9 * x3,6) - (x5,6 * x3,9)) / x3,6 = ((1 * 0.4) - (0 * 0)) / 0.4 = 1; Maxx1 = ((Cb1 * x1,1) + (Cb2 * x2,1) + (Cb3 * x3,1) + (Cb4 * x4,1) + (Cb5 * x5,1) ) - kx1 = ((0 * 0.75) + (0 * 0) + (0 * 2.5) + (4 * 1.25) + (-M * 0) ) - 3 = 2; Maxx5 = ((Cb1 * x1,5) + (Cb2 * x2,5) + (Cb3 * x3,5) + (Cb4 * x4,5) + (Cb5 * x5,5) ) - kx5 = ((0 * -0.25) + (0 * 0) + (0 * 0.5) + (4 * 0.25) + (-M * 0) ) - 0 = 1; Maxx6 = ((Cb1 * x1,6) + (Cb2 * x2,6) + (Cb3 * x3,6) + (Cb4 * x4,6) + (Cb5 * x5,6) ) - kx6 = ((0 * 0) + (0 * 0) + (0 * 1) + (4 * 0) + (-M * 0) ) - 0 = 0; Maxx8 = ((Cb1 * x1,8) + (Cb2 * x2,8) + (Cb3 * x3,8) + (Cb4 * x4,8) + (Cb5 * x5,8) ) - kx8 = ((0 * 0) + (0 * 0) + (0 * -1) + (4 * 0) + (-M * 0) ) - -M = M; Since there are no negative values among the estimates of the controlled variables, the current table has an optimal solution. P1 = (P1 * x3,1) - (x1,1 * P3) / x3,1 = ((525 * 5) - (2 * 700)) / 5 = 245; P2 = (P2 * x3,1) - (x2,1 * P3) / x3,1 = ((225 * 5) - (0 * 700)) / 5 = 225; P4 = (P4 * x3,1) - (x4,1 * P3) / x3,1 = ((75 * 5) - (0 * 700)) / 5 = 75; P5 = (P5 * x3,1) - (x5,1 * P3) / x3,1 = ((0 * 5) - (0 * 700)) / 5 = 0; x1,1 = ((x1,1 * x3,1) - (x1,1 * x3,1)) / x3,1 = ((2 * 5) - (2 * 5)) / 5 = 0; x1,3 = ((x1,3 * x3,1) - (x1,1 * x3,3)) / x3,1 = ((1 * 5) - (2 * 0)) / 5 = 1; x1,4 = ((x1,4 * x3,1) - (x1,1 * x3,4)) / x3,1 = ((0 * 5) - (2 * 0)) / 5 = 0; x1,5 = ((x1,5 * x3,1) - (x1,1 * x3,5)) / x3,1 = ((0 * 5) - (2 * 1)) / 5 = -0.4; x1,6 = ((x1,6 * x3,1) - (x1,1 * x3,6)) / x3,1 = ((0.5 * 5) - (2 * 2)) / 5 = -0.3; x1,7 = ((x1,7 * x3,1) - (x1,1 * x3,7)) / x3,1 = ((0 * 5) - (2 * 0)) / 5 = 0; x1,8 = ((x1,8 * x3,1) - (x1,1 * x3,8)) / x3,1 = ((-0.5 * 5) - (2 * -2)) / 5 = 0.3; x1,9 = ((x1,9 * x3,1) - (x1,1 * x3,9)) / x3,1 = ((0 * 5) - (2 * 0)) / 5 = 0; x2,1 = ((x2,1 * x3,1) - (x2,1 * x3,1)) / x3,1 = ((0 * 5) - (0 * 5)) / 5 = 0; x2,3 = ((x2,3 * x3,1) - (x2,1 * x3,3)) / x3,1 = ((0 * 5) - (0 * 0)) / 5 = 0; x2,4 = ((x2,4 * x3,1) - (x2,1 * x3,4)) / x3,1 = ((1 * 5) - (0 * 0)) / 5 = 1; x2,5 = ((x2,5 * x3,1) - (x2,1 * x3,5)) / x3,1 = ((0 * 5) - (0 * 1)) / 5 = 0; x2,6 = ((x2,6 * x3,1) - (x2,1 * x3,6)) / x3,1 = ((0 * 5) - (0 * 2)) / 5 = 0; x2,7 = ((x2,7 * x3,1) - (x2,1 * x3,7)) / x3,1 = ((0 * 5) - (0 * 0)) / 5 = 0; x2,8 = ((x2,8 * x3,1) - (x2,1 * x3,8)) / x3,1 = ((0 * 5) - (0 * -2)) / 5 = 0; x2,9 = ((x2,9 * x3,1) - (x2,1 * x3,9)) / x3,1 = ((0 * 5) - (0 * 0)) / 5 = 0; x4,1 = ((x4,1 * x3,1) - (x4,1 * x3,1)) / x3,1 = ((0 * 5) - (0 * 5)) / 5 = 0; x4,3 = ((x4,3 * x3,1) - (x4,1 * x3,3)) / x3,1 = ((0 * 5) - (0 * 0)) / 5 = 0; x4,4 = ((x4,4 * x3,1) - (x4,1 * x3,4)) / x3,1 = ((0 * 5) - (0 * 0)) / 5 = 0; x4,5 = ((x4,5 * x3,1) - (x4,1 * x3,5)) / x3,1 = ((0 * 5) - (0 * 1)) / 5 = 0; x4,6 = ((x4,6 * x3,1) - (x4,1 * x3,6)) / x3,1 = ((-0.5 * 5) - (0 * 2)) / 5 = -0.5; x4,7 = ((x4,7 * x3,1) - (x4,1 * x3,7)) / x3,1 = ((0 * 5) - (0 * 0)) / 5 = 0; x4,8 = ((x4,8 * x3,1) - (x4,1 * x3,8)) / x3,1 = ((0.5 * 5) - (0 * -2)) / 5 = 0.5; x4,9 = ((x4,9 * x3,1) - (x4,1 * x3,9)) / x3,1 = ((0 * 5) - (0 * 0)) / 5 = 0; x5,1 = ((x5,1 * x3,1) - (x5,1 * x3,1)) / x3,1 = ((0 * 5) - (0 * 5)) / 5 = 0; x5,3 = ((x5,3 * x3,1) - (x5,1 * x3,3)) / x3,1 = ((0 * 5) - (0 * 0)) / 5 = 0; x5,4 = ((x5,4 * x3,1) - (x5,1 * x3,4)) / x3,1 = ((0 * 5) - (0 * 0)) / 5 = 0; x5,5 = ((x5,5 * x3,1) - (x5,1 * x3,5)) / x3,1 = ((0 * 5) - (0 * 1)) / 5 = 0; x5,6 = ((x5,6 * x3,1) - (x5,1 * x3,6)) / x3,1 = ((0 * 5) - (0 * 2)) / 5 = 0; x5,7 = ((x5,7 * x3,1) - (x5,1 * x3,7)) / x3,1 = ((-1 * 5) - (0 * 0)) / 5 = -1; x5,8 = ((x5,8 * x3,1) - (x5,1 * x3,8)) / x3,1 = ((0 * 5) - (0 * -2)) / 5 = 0; x5,9 = ((x5,9 * x3,1) - (x5,1 * x3,9)) / x3,1 = ((1 * 5) - (0 * 0)) / 5 = 1; Maxx1 = ((Cb1 * x1,1) + (Cb2 * x2,1) + (Cb3 * x3,1) + (Cb4 * x4,1) + (Cb5 * x5,1) ) - kx1 = ((0 * 0) + (0 * 0) + (3 * 1) + (4 * 0) + (-M * 0) ) - 3 = 0; Maxx2 = ((Cb1 * x1,2) + (Cb2 * x2,2) + (Cb3 * x3,2) + (Cb4 * x4,2) + (Cb5 * x5,2) ) - kx2 = ((0 * 0) + (0 * 0) + (3 * 0) + (4 * 1) + (-M * 0) ) - 4 = 0; Maxx3 = ((Cb1 * x1,3) + (Cb2 * x2,3) + (Cb3 * x3,3) + (Cb4 * x4,3) + (Cb5 * x5,3) ) - kx3 = ((0 * 1) + (0 * 0) + (3 * 0) + (4 * 0) + (-M * 0) ) - 0 = 0; Maxx4 = ((Cb1 * x1,4) + (Cb2 * x2,4) + (Cb3 * x3,4) + (Cb4 * x4,4) + (Cb5 * x5,4) ) - kx4 = ((0 * 0) + (0 * 1) + (3 * 0) + (4 * 0) + (-M * 0) ) - 0 = 0; Maxx5 = ((Cb1 * x1,5) + (Cb2 * x2,5) + (Cb3 * x3,5) + (Cb4 * x4,5) + (Cb5 * x5,5) ) - kx5 = ((0 * -0.4) + (0 * 0) + (3 * 0.2) + (4 * 0) + (-M * 0) ) - 0 = 0.6; Maxx6 = ((Cb1 * x1,6) + (Cb2 * x2,6) + (Cb3 * x3,6) + (Cb4 * x4,6) + (Cb5 * x5,6) ) - kx6 = ((0 * -0.3) + (0 * 0) + (3 * 0.4) + (4 * -0.5) + (-M * 0) ) - 0 = -0.8; Maxx7 = ((Cb1 * x1,7) + (Cb2 * x2,7) + (Cb3 * x3,7) + (Cb4 * x4,7) + (Cb5 * x5,7) ) - kx7 = ((0 * 0) + (0 * 0) + (3 * 0) + (4 * 0) + (-M * -1) ) - 0 = M; Maxx8 = ((Cb1 * x1,8) + (Cb2 * x2,8) + (Cb3 * x3,8) + (Cb4 * x4,8) + (Cb5 * x5,8) ) - kx8 = ((0 * 0.3) + (0 * 0) + (3 * -0.4) + (4 * 0.5) + (-M * 0) ) - -M = M+0.8; Maxx9 = ((Cb1 * x1,9) + (Cb2 * x2,9) + (Cb3 * x3,9) + (Cb4 * x4,9) + (Cb5 * x5,9) ) - kx9 = ((0 * 0) + (0 * 0) + (3 * 0) + (4 * 0) + (-M * 1) ) - -M = 0; For the results of the calculations of the previous iteration, we remove the variable from the basis x1 and put in her place x6. Final Tableau always contains the primal as well as the dual
Linear Programming in Python Watch on Exercise: Soft Drink Production A simple production planning problem is given by the use of two ingredients A and B that produce products 1 and 2. 1 Now we are prepared to pivot again. = x The first one is called Wolfe's modified simplex method (I guess), which is actually an active set method. 2 As long as there are no repetitive entering variables can be selected, the optimal values will be found. Since the coefficient in the first row is 1 and 4 for the second row, the first row should be pivoted. {\displaystyle \phi } In this section, we will solve the standard linear programming minimization problems using the simplex method. he solution by the simplex method is not as difficult as it might seem at first glance. We select the smaller one to ensure we have a corner point that is in our feasible region. + j When you are using a linear programming calculator, you To embed this widget in a post on your WordPress blog, copy and paste the shortcode below into the HTML source: To add a widget to a MediaWiki site, the wiki must have the. x 0 {\displaystyle x_{3}=1.2} + The potential constraints are raised from multiple perspectives including policy restriction, budget concerns as well as farmland area. WebLinear programming solver Finds the minimum of a problem specified by min x f T x such that { A x b, A e q x = b e q, l b x u b. f, x, b, beq, lb , and ub are vectors, and A and Aeq are matrices. m To identify the solution set, focus we focus only on the columns with exactly one nonzero entry \(-\) these are called active variables (columns with more than one non-zero entry are thus called inactive variables). b 3 1 The simplex method is commonly used in many programming problems. Basically, it 2 WebLearn More Simplex Method - Linear Programming In this calculator you will be able to solve exercises with the two-phase method. j 2 6.4 There is a comprehensive manual included with the software. Therefore, if an LP has an optimal solution, there must be an extreme point of the feasible region that is optimal. example 1 1 i Looking at the ratios, \(\frac{4}{1/2}=8\) and \(\frac{2}{5/2}=0.8\). 1 1 We provide quick and easy solutions to all your homework problems. For an LP optimization problem, there is only one extreme point of the LP's feasible region regarding every basic feasible solution. 2 a We will present the algorithm for solving, however, note that it is not entirely intuitive. s 2 First off, matrices dont do well with inequalities. x 0 Step 3: Click on the Optimize the Function button. 3 Every dictionary will have m basic variables which form the feasible area, as well as n non-basic variables which compose the objective function. I learned more with this app than school if I'm going to be completely honest. WebWe can use Excels Solver to solve this linear programming problem, employing the Simplex Linear Programming method, where each data element results in two constraints. 1 you can use this to draw tables you need to install numpy to use this program. How, then, do we avoid this? In this section, we will solve the standard linear programming minimization problems using the simplex method. Minimize 5 x 1? It is one of the popular methods that are used to avail of the
i amazing role in solving the linear programming problems with ease. 1 t {\displaystyle x_{2}=0} z This alone discourages the use of inequalities in matrices. 1 In order to use the simplex method, either by technology or by hand, we must set up an initial simplex tableau, which is a matrix containing information about the linear programming problem we wish to solve. 0.5 {\displaystyle x_{3}} Potential Method. Learn More Gantt Chart - Project Management Try our simple Gantt Chart Online Maker. of a data set for a given linear problem step by step. 2 {\displaystyle x_{1}=0.4} x see how to set it up.). This takes care of the inequalities for us. 1 about this calculator is at it easily solving the problems
Simplex method is an approach to solving linear programming models by hand using slack variables, tableaus, and pivot variables as a means to finding the optimal solution of an optimization problem. x { x 2 0 + points. 1 0 1 If you're looking for help with your homework, our team of experts have you covered. = Do not use commas in large numbers while using the simplex
Also it depicts every step so that the user can understand how the problem is solved. + 3 {\displaystyle {\begin{array}{c c c c c c c | r}x_{1}&x_{2}&x_{3}&s_{1}&s_{2}&s_{3}&z&b\\\hline 2&1&1&1&0&0&0&2\\1&2&3&0&1&0&0&4\\2&2&1&0&0&1&0&8\\\hline -4&-1&-4&0&0&0&1&0\end{array}}}. The decision of which entering variable should be selected at first place should be made based on the consideration that there usually are multiple constraints (n>1). 0.8 3 As in the pivot process, the coefficient for the selected pivot element should be one, meaning the reciprocal of this coefficient should be multiplied to every element within this row. Select the correct choice below and fill in any answer boxes present in your choice. 2 3 . 4 2. x 1? WebSimplex method calculator - The Simplex algorithm is a popular method for numerical solution of the linear programming problem. 2 2 Solve Now. A simple calculator and some simple steps to use it. { "3.01:_Inequalities_in_One_Variable" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.
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A user's guide is also available to quickly learn to use the PHPSimplex tool. . The simplex method for quadratic programming. The boxed value is now called our pivot. 1 0 Then we can add -1 times the top row to the second row, and 9 times the top row to the third row. So, after getting basic information about what it is, lets see how 2 1 + 25 x 2?? represent the optimal solution in the form of a graph of the given 6.4 2 WebOnline Calculator: Simplex Method ; English; Hungarian Method. 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